{"id":19865,"date":"2022-06-30T06:46:52","date_gmt":"2022-06-30T06:46:52","guid":{"rendered":"https:\/\/mdr.foobrdigital.com\/?p=5109"},"modified":"2022-06-30T06:46:52","modified_gmt":"2022-06-30T06:46:52","slug":"solved-exercises-on-gay-lussacs-law","status":"publish","type":"post","link":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/2022\/06\/30\/solved-exercises-on-gay-lussacs-law\/","title":{"rendered":"Solved Exercises on Gay-Lussac`s Law"},"content":{"rendered":"\n<h3 class=\"wp-block-heading\">Exercise 1<\/h3>\n\n\n\n<p><strong>The pressure of a gas in a cylinder when it is heated to a temperature of 250K is 1.5 atm. What was the initial temperature of the gas if its initial pressure was 1 atm?<\/strong><\/p>\n\n\n\n<p>Given,<\/p>\n\n\n\n<p>Initial pressure, P<sub>1<\/sub>&nbsp;= 1 atm<\/p>\n\n\n\n<p>Final pressure, P<sub>2<\/sub>&nbsp;= 1.5 atm<\/p>\n\n\n\n<p>Final temperature, T<sub>2<\/sub>&nbsp;= 250 K<\/p>\n\n\n\n<p>As per Gay-Lussac\u2019s Law, P<sub>1<\/sub>T<sub>2<\/sub>&nbsp;= P<sub>2<\/sub>T<sub>1<\/sub><\/p>\n\n\n\n<p>Therefore, T<sub>1<\/sub>&nbsp;= (P<sub>1<\/sub>T<sub>2<\/sub>)\/P<sub>2<\/sub>&nbsp;= (1*250)\/(1.5) = 166.66 Kelvin.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Exercise 2<\/h3>\n\n\n\n<p><strong>At a temperature of 300 K, the pressure of the gas in a deodorant can is 3 atm. Calculate the pressure of the gas when it is heated to 900 K.<\/strong><\/p>\n\n\n\n<p>Initial pressure, P<sub>1<\/sub>&nbsp;= 3 atm<\/p>\n\n\n\n<p>Initial temperature, T<sub>1<\/sub>&nbsp;= 300K<\/p>\n\n\n\n<p>Final temperature, T<sub>2<\/sub>&nbsp;= 900 K<\/p>\n\n\n\n<p>Therefore, final pressure (P<sub>2<\/sub>) = (P<sub>1<\/sub>T<sub>2<\/sub>)\/T<sub>1<\/sub>&nbsp;= (3 atm*900K)\/300K = 9 atm.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Exercise 1 The pressure of a gas in a cylinder when it is heated to a temperature of 250K is 1.5 atm. What was the initial temperature of the gas if its initial pressure was 1 atm? Given, Initial pressure, P1&nbsp;= 1 atm Final pressure, P2&nbsp;= 1.5 atm Final temperature, T2&nbsp;= 250 K As per [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[87],"tags":[],"_links":{"self":[{"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/posts\/19865"}],"collection":[{"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/comments?post=19865"}],"version-history":[{"count":0,"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/posts\/19865\/revisions"}],"wp:attachment":[{"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/media?parent=19865"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/categories?post=19865"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/tags?post=19865"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}