{"id":3953,"date":"2022-06-01T07:57:35","date_gmt":"2022-06-01T07:57:35","guid":{"rendered":"https:\/\/mdr.foobrdigital.com\/?p=3953"},"modified":"2022-06-01T07:57:35","modified_gmt":"2022-06-01T07:57:35","slug":"electric-power","status":"publish","type":"post","link":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/2022\/06\/01\/electric-power\/","title":{"rendered":"Electric Power"},"content":{"rendered":"\n

Electric power definition<\/h3>\n\n\n\n

The electric power P is equal to the energy consumption E divided by the consumption time t:<\/p>\n\n\n\n

\"P=\\frac{E}{t}\"\/<\/figure>\n\n\n\n

P is the electric power in watt (W).<\/p>\n\n\n\n

E is the energy consumption in joule (J).<\/p>\n\n\n\n

t is the time in seconds (s).<\/p>\n\n\n\n

Example<\/h4>\n\n\n\n

Find the electric power of an electrical circuit that consumes 120 joules for 20 seconds.<\/p>\n\n\n\n

Solution:<\/p>\n\n\n\n

E<\/em> = 120J<\/p>\n\n\n\n

t<\/em> = 20s<\/p>\n\n\n\n

P<\/em> = E<\/em> \/ t<\/em> = 120J \/ 20s = 6W<\/p>\n\n\n\n

<\/a>Electric power calculation<\/h3>\n\n\n\n

P<\/em> = V <\/em>\u22c5 I<\/em><\/p>\n\n\n\n

or<\/p>\n\n\n\n

P = I <\/sup><\/em>2 <\/sup>\u22c5 R<\/em><\/p>\n\n\n\n

or<\/p>\n\n\n\n

P = V <\/sup><\/em>2<\/sup>\/ R<\/em><\/p>\n\n\n\n

P is the electric power in watt (W).<\/p>\n\n\n\n

V is the voltage in volts (V).<\/p>\n\n\n\n

I is the current in amps (A).<\/p>\n\n\n\n

R is the resistance in ohms (\u03a9).<\/p>\n\n\n\n

<\/a>Power of AC circuits<\/h3>\n\n\n\n

The formulas are for single phase AC power.<\/p>\n\n\n\n

For 3 phase AC power:<\/p>\n\n\n\n

 When line to line voltage (VL-L<\/sub>) is used in the formula, multiply the single phase power by square root of 3 (\u221a3=1.73).<\/p>\n\n\n\n

When line to zero voltage (VL-0<\/sub>) is used in the formula, multiply the single phase power by 3.<\/p>\n\n\n\n

Real power<\/h4>\n\n\n\n

Real or true power is the power that is used to do the work on the load.<\/p>\n\n\n\n

P<\/em> = Vrms<\/sub><\/em> Irms<\/sub><\/em> cos<\/em> \u03c6<\/em><\/p>\n\n\n\n

P      <\/em>is the real power in watts [W]<\/p>\n\n\n\n

Vrms<\/sub>  is the rms voltage = Vpeak<\/sub>\/\u221a2 in Volts [V]<\/p>\n\n\n\n

Irms<\/sub>   is the rms current = Ipeak<\/sub>\/\u221a2 in Amperes [A]<\/p>\n\n\n\n

\u03c6 <\/em>     is theimpedance phase angle = phase difference between voltage and current.<\/p>\n\n\n\n

 <\/h5>\n\n\n\n

Reactive power<\/h4>\n\n\n\n

Reactive power is the power that is wasted and not used to do work on the load.<\/p>\n\n\n\n

Q<\/em> = Vrms<\/sub><\/em> Irms<\/sub><\/em> sin<\/em> \u03c6<\/em><\/p>\n\n\n\n

Q      <\/em>is the reactive power in volt-ampere-reactive [VAR]<\/p>\n\n\n\n

Vrms<\/sub>  is the rms voltage = Vpeak<\/sub>\/\u221a2 in Volts [V]<\/p>\n\n\n\n

Irms<\/sub>   is the rms current = Ipeak<\/sub>\/\u221a2 in Amperes [A]<\/p>\n\n\n\n

\u03c6 <\/em>     is theimpedance phase angle = phase difference between voltage and current.<\/p>\n\n\n\n

 <\/h5>\n\n\n\n

Apparent power<\/h4>\n\n\n\n

The apparent power is the power that is supplied to the circuit.<\/p>\n\n\n\n

S<\/em> = Vrms<\/sub><\/em> Irms<\/sub><\/em><\/p>\n\n\n\n

S      <\/em>is the apparent power in Volt-amper [VA]<\/p>\n\n\n\n

Vrms<\/sub>  is the rms voltage = Vpeak<\/sub>\/\u221a2 in Volts [V]<\/p>\n\n\n\n

Irms<\/sub>   is the rms current = Ipeak<\/sub>\/\u221a2 in Amperes [A]<\/p>\n\n\n\n

 <\/h5>\n\n\n\n

Real \/ reactive \/ apparent powers relation<\/h4>\n\n\n\n

The real power P and reactive power Q give together the apparent power S:<\/p>\n\n\n\n

P<\/em>2<\/sup> + Q<\/em>2<\/sup> = S<\/em>2<\/sup><\/p>\n\n\n\n

P      <\/em>is the real power in watts [W]<\/p>\n\n\n\n

Q      <\/em>is the reactive power in volt-ampere-reactive [VAR]<\/p>\n\n\n\n

S      <\/em>is the apparent power in Volt-amper [VA]<\/p>\n","protected":false},"excerpt":{"rendered":"

Electric power definition The electric power P is equal to the energy consumption E divided by the consumption time t: P is the electric power in watt (W). E is the energy consumption in joule (J). t is the time in seconds (s). Example Find the electric power of an electrical circuit that consumes 120 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[258],"tags":[],"_links":{"self":[{"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/posts\/3953"}],"collection":[{"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/comments?post=3953"}],"version-history":[{"count":0,"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/posts\/3953\/revisions"}],"wp:attachment":[{"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/media?parent=3953"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/categories?post=3953"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/tags?post=3953"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}