{"id":3994,"date":"2022-06-01T08:17:11","date_gmt":"2022-06-01T08:17:11","guid":{"rendered":"https:\/\/mdr.foobrdigital.com\/?p=3994"},"modified":"2022-06-01T08:17:11","modified_gmt":"2022-06-01T08:17:11","slug":"ohms-law-2","status":"publish","type":"post","link":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/2022\/06\/01\/ohms-law-2\/","title":{"rendered":"Ohm&#8217;s Law"},"content":{"rendered":"\n<p>Ohm&#8217;s law shows a linear relationship between the voltage and the current in an electrical circuit.<\/p>\n\n\n\n<p>The resistor&#8217;s voltage drop and resistance set the DC current flow through the resistor.<\/p>\n\n\n\n<p>With water flow analogy we can imagine the electric current as water current through pipe, the resistor as a thin pipe that limits the water flow, the voltage as height difference of the water that enables the water flow.<\/p>\n\n\n\n<ul><li><a href=\"https:\/\/www.rapidtables.com\/electric\/ohms-law.html#formula\">Ohm&#8217;s law formula<\/a><\/li><li><a href=\"https:\/\/www.rapidtables.com\/electric\/ohms-law.html#ac\">Ohm&#8217;s law for AC circuit<\/a><\/li><li><a href=\"https:\/\/www.rapidtables.com\/calc\/electric\/ohms-law-calculator.html\">Ohm&#8217;s law calculator<\/a><\/li><\/ul>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.rapidtables.com\/electric\/ohm's%20law\/basic%20circuit.PNG\" alt=\"\"\/><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\"><a><\/a>Ohm&#8217;s law formula<\/h2>\n\n\n\n<p>The resistor&#8217;s current I in amps (A) is equal to the resistor&#8217;s voltage V in volts (V) divided by the resistance R in ohms (\u03a9):<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.rapidtables.com\/electric\/ohm's%20law\/Ohm's%20law.gif\" alt=\"\"\/><\/figure>\n\n\n\n<p><em>V<\/em>&nbsp;is the voltage drop of the resistor, measured in Volts (V). In some cases Ohm&#8217;s law uses the letter&nbsp;<em>E<\/em>&nbsp;to represent voltage.&nbsp;<em>E<\/em>&nbsp;denotes electromotive force.<\/p>\n\n\n\n<p><em>I<\/em>&nbsp;is the electrical current flowing through the resistor, measured in&nbsp; Amperes (A)<\/p>\n\n\n\n<p><em>R<\/em>&nbsp;is the resistance of the resistor, measured in Ohms (\u03a9)<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Voltage calculation<\/h4>\n\n\n\n<p>When we know the current and resistance, we can calculate the voltage.<\/p>\n\n\n\n<p>The voltage V in volts (V) is equal to the to the current I in amps (A) times the resistance R in ohms (\u03a9):<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.rapidtables.com\/electric\/ohm's%20law\/Ohm's%20law%20V.gif\" alt=\"V=I\\times R\"\/><\/figure>\n\n\n\n<h4 class=\"wp-block-heading\">Resistance calculation<\/h4>\n\n\n\n<p>When we know the voltage and the current, we can calculate the resistance.<\/p>\n\n\n\n<p>The resistance R in ohms (\u03a9) is equal to the voltage V in volts (V) divided by the current I in amps (A):<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.rapidtables.com\/electric\/ohm's%20law\/Ohm's%20law%20R.gif\" alt=\"R=\\frac{V}{I}\"\/><\/figure>\n\n\n\n<p>Since the current is set by the values of the voltage and resistance, the Ohm&#8217;s law formula can show that:<\/p>\n\n\n\n<ul><li>If we increase the voltage, the current will increase.<\/li><li>If we increase the resistance, the current will reduce.<\/li><\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">Example #1<\/h4>\n\n\n\n<p>Find the current of an electrical circuit that has resistance of 50 Ohms and voltage supply of 5 Volts.<\/p>\n\n\n\n<p>Solution:<\/p>\n\n\n\n<p><em>V<\/em>&nbsp;= 5V<\/p>\n\n\n\n<p><em>R<\/em>&nbsp;= 50\u03a9<\/p>\n\n\n\n<p><em>I<\/em>&nbsp;=&nbsp;<em>V \/ R<\/em>&nbsp;= 5V \/ 50\u03a9 = 0.1A = 100mA<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Example #2<\/h4>\n\n\n\n<p>Find the resistance of an electrical circuit that has voltage supply of 10 Volts and current of 5mA.<\/p>\n\n\n\n<p>Solution:<\/p>\n\n\n\n<p><em>V<\/em>&nbsp;= 10V<\/p>\n\n\n\n<p><em>I<\/em>&nbsp;= 5mA = 0.005A<\/p>\n\n\n\n<p><em>R<\/em>&nbsp;=&nbsp;<em>V \/ I<\/em>&nbsp;= 10V \/ 0.005A = 2000\u03a9 = 2k\u03a9<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><a><\/a>Ohm&#8217;s Law for AC Circuit<\/h2>\n\n\n\n<p>The load&#8217;s current I in amps (A) is equal to the load&#8217;s voltage V<sub>Z<\/sub>=V in volts (V) divided by the impedance Z in ohms (\u03a9):<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.rapidtables.com\/electric\/ohm's%20law\/Ohm'w%20law%20AC.gif\" alt=\"\"\/><\/figure>\n\n\n\n<p><em>V<\/em>&nbsp;is the voltage drop on the load, measured in Volts (V)<\/p>\n\n\n\n<p><em>I<\/em>&nbsp;is the electrical current, measured in Amps (A)<\/p>\n\n\n\n<p><em>Z<\/em>&nbsp;is the impedance of the load, measured in Ohms (\u03a9)<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Example #3<\/h4>\n\n\n\n<p>Find the current of an AC circuit, that has voltage supply of 110V\u221f70\u00b0 and load of 0.5k\u03a9\u221f20\u00b0.<\/p>\n\n\n\n<p>Solution:<\/p>\n\n\n\n<p><em>V<\/em>&nbsp;= 110V\u221f70\u00b0<\/p>\n\n\n\n<p><em>Z<\/em>&nbsp;= 0.5k\u03a9\u221f20\u00b0 = 500\u03a9\u221f20\u00b0<\/p>\n\n\n\n<p><em>I<\/em>&nbsp;=&nbsp;<em>V<\/em>&nbsp;\/&nbsp;<em>Z&nbsp;<\/em>= 110V\u221f70\u00b0 \/ 500\u03a9\u221f20\u00b0 = (110V \/ 500\u03a9) \u221f (70\u00b0-20\u00b0) = 0.22A \u221f50\u00b0<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><a><\/a>Ohm&#8217;s Law Calculator (short form)<\/h3>\n\n\n\n<p>Ohm&#8217;s law calculator: calculates the relation between Voltage, Current and Resistance.<\/p>\n\n\n\n<p>Enter&nbsp;<strong>2<\/strong>&nbsp;values to get the third value and press the&nbsp;<em>Calculate<\/em>button:<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table><tbody><tr><td>&nbsp;<\/td><td>&nbsp;<\/td><td>&nbsp;<\/td><td>&nbsp;<\/td><td>&nbsp;<\/td><td>&nbsp;<\/td><td>&nbsp;<\/td><\/tr><tr><td>&nbsp;<\/td><td>Enter Resistance:<\/td><td><em>R<\/em><\/td><td>=<\/td><td><\/td><td>ohms (\u03a9)<\/td><td>&nbsp;<\/td><\/tr><tr><td>&nbsp;<\/td><td>Enter Current:<\/td><td><em>I<\/em><\/td><td>=<\/td><td><\/td><td>amps (A)<\/td><td>&nbsp;<\/td><\/tr><tr><td>&nbsp;<\/td><td>Enter Voltage:<\/td><td><em>V<\/em><\/td><td>=<\/td><td><\/td><td>volts (V)<\/td><td>&nbsp;<\/td><\/tr><tr><td>&nbsp;<\/td><td>&nbsp;<\/td><td>&nbsp;<\/td><td>&nbsp;<\/td><td>&nbsp;<\/td><td>&nbsp;<\/td><td>&nbsp;<\/td><\/tr><tr><td>&nbsp;<\/td><td><\/td><td><\/td><td><\/td><td><\/td><td><\/td><td>&nbsp;<\/td><\/tr><tr><td>&nbsp;<\/td><td>&nbsp;<\/td><td>&nbsp;<\/td><td>&nbsp;<\/td><td>&nbsp;<\/td><td>&nbsp;<\/td><td>&nbsp;<\/td><\/tr><\/tbody><\/table><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Ohm&#8217;s law shows a linear relationship between the voltage and the current in an electrical circuit. The resistor&#8217;s voltage drop and resistance set the DC current flow through the resistor. With water flow analogy we can imagine the electric current as water current through pipe, the resistor as a thin pipe that limits the water [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[413],"tags":[],"_links":{"self":[{"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/posts\/3994"}],"collection":[{"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/comments?post=3994"}],"version-history":[{"count":0,"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/posts\/3994\/revisions"}],"wp:attachment":[{"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/media?parent=3994"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/categories?post=3994"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mudassirbackup.infinitycodestudio.com\/index.php\/wp-json\/wp\/v2\/tags?post=3994"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}